2014년 3월 1일 토요일

Euler Project: Problem 6

The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Prelude> ((^2) $ sum [1..100]) - (sum $ map (^2) [1..100])
25164150

댓글 없음:

댓글 쓰기