Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:
21 22 23 24 25
20 7 8 9 10
19 6 1 2 11
18 5 4 3 12
17 16 15 14 13
20 7 8 9 10
19 6 1 2 11
18 5 4 3 12
17 16 15 14 13
It can be verified that the sum of the numbers on the diagonals is 101.
What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way?
main :: IO()
main = print $ 1 + sumOf2ndTo1001Diag
sumOf2ndTo1001Diag :: Int
sumOf2ndTo1001Diag = sum $ map sumCurrDiag inputData
--초항: 예를 들어 3x3은, prev인 1x1 + (3-1).
iniNum :: (Int, Int) -> Int
iniNum (prev, curr) = prev * prev + (curr - 1)
--3x3에서는 iniNum에서 (3-1)의 등차수열.
sumCurrDiag :: (Int, Int) -> Int
sumCurrDiag (prev, curr) = 2 * ( 2 * iniNum (prev, curr) + 3 * (curr - 1))
--sumCurrDiag (prev, curr) = iniNum (prev, curr) * 4 + (curr - 1) * 6
inputData :: [(Int, Int)]
inputData = zip baseData (tail baseData)
baseData :: [Int]
baseData = [1,3..1001]
*Main> main
669171001
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